New SFPs in 'da house!
 

Been reading in-depth Emile's posts on another forum about the SFPs that he found to be the best-sounding SFPs, and what he recommends for use with the Taiko Extreme. So, today I got in two of 'em in to try out.

I got these from Planet Technology Corp., and they are 1000Base-LX single-mode SFPs from MGB-TLX that support transmission up to 20KM over 9/125 fiber.

https://photos.imageevent.com/puma_c...GB-TLX-SFP.jpg

https://photos.imageevent.com/puma_c...P-module_1.jpg

I also got in some Corning LC/LC 9/125 fiber to try out as well vs. the Tripp-Lite LC/LC fiber I'm currently using (which has been working fine).
https://photos.imageevent.com/puma_c...LC-cable_1.jpg

The nice thing about the Lumin P1 is I can run fiber directly from the EtherREGEN in the "remote server room" straight in to the back of the Lumin P1, and be done. No messin' around with network bridges, power supplies for network bridges, power cables for the power supplies for the network bridges, power cables for the DAC, Ethernet cables for the network bridge, USB cables for the DAC, interconnects from the DAC to the preamp, blah, blah, blah...:yuck:

Basically, with the P1, it's "one and done"! Simple is GOOD. :thumbsup:

Going to start out with the optical transceivers first, and then when I get a chance, I'll install the run of the new Corning fiber.

Stay tuned...

Hey Stephen.
You think you can relay your findings as a 3rd grade English teacher instead of Scientist.
Just saying...:D

Sure!

iħ∂/∂ψ(r, t) = Ĥψ(r, t)

No, wait....:p

Of course.
However, The equation you have written is the time-dependent Schrödinger equation in which Ĥ is the Hamiltonian operator and ψ(r, t) is the wave function of a quantum system.

The Hamiltonian operator represents the total energy of the system and is given by:

Ĥ = - (ħ^2/2m) ∇^2 + V(r)

where ħ is the reduced Planck constant, m is the mass of the particle, ∇^2 is the Laplace operator, and V(r) is the potential energy function.

The time-dependent Schrödinger equation describes how the wave function ψ evolves in time, given the Hamiltonian Ĥ. The equation you have written states that the partial derivative of ψ with respect to time is proportional to Ĥ times ψ.

To solve the time-dependent Schrödinger equation, one needs to determine the wave function ψ that satisfies the equation for a given Hamiltonian Ĥ and initial conditions. This can be a challenging task in general, and various approximation methods are often used to simplify the problem.

Any questions?

Exactly right!
Those pesky Hamiltonians! I tell ya what! :p

Along these lines, I’ve got a really interesting podcast Lex Fridman just posted I’ll send to you; he interviews a really interesting astrophysicist. Cheers!

Why not encrypt this thread too just for fun. :lmao:

Yes - who are you?

I read the title of this thread and went Uggh. Playing around with SFP cages and cables may be one of the last areas of my digital nervosa left and I had thought I had fought it off. ��

Past experience says we can lay back and wait for Stephen to do the work for us.[emoji41]

Wise advice Tony. But it still may cost me $. ;)